need help with a diving board script

i found this script in a tramploine or something i was wondering if it was possible to combine the 2 llPushObejct parts into one since it seems only one is working at a time.

float force_amount = 100.0;
float fwd_amount = 100.0;

default
{
    collision(integer tnum)
    {
        llTriggerSound("trampoline", 1.0);
        if (llDetectedType(0) & AGENT)
            llPushObject(llDetectedKey(0), force_amount*llRot2Up(llGetRot()), ZERO_VECTOR, FALSE);//want to combine these 2
            llPushObject(llDetectedKey(0), fwd_amount*llRot2Fwd(llGetRot()), ZERO_VECTOR, FALSE);//want to combine these 2
            llSetText("Touch to dive!", <1.0,0.0,0.0>, 1);
    }
}

Lol, anyone? I know there is some math involved but I'm not good with that. I know you math wizes would like to take a stab at that.

lol, nevermind with the help of a friend we figured it out.

float force_amount = 100.0;
float fwd_amount = -100.0;

default
{
    state_entry()
    {
        llSetText("Touch to dive!", <1.0,0.0,0.0>, 1);
    }
    collision(integer tnum)
    {
        llTriggerSound("trampoline", 1.0);
        if (llDetectedType(0) & AGENT)
        {
            llPushObject(llDetectedKey(0), force_amount*llRot2Up(llGetRot()) + fwd_amount*llRot2Fwd(llGetRot()), ZERO_VECTOR, FALSE);
        }
    }
}

The behaviour of the second script will be a little different then the first one though.

This has to do with the way the force of llPushObject is calculated. It is dependent of the distance the 'pushed' object/avatar is from the pushing object.

In the first example the avatar is already pushed in the air by the first call, so it's a little further apart from the pushing object, when the second call triggers the forward push.

In the second script the object gets both pushes at the same distance from the pushing object, so the forward strength will probably be a little greater.

As the push calls follow rapidly after another in the first script, the resulting difference should be negligible though.