Finding a percent

Hey all,
I have the following code:

percent_done = (integer)(time*0.01) * (current_length);

This is supposed to get the (integer)'percent_done', as time being the 'time' in seconds into the song and the 'current_length' being the total length in seconds of the song. This doesn't return the integer correctly, and I was wondering if someone could help me out. Thanks.

I think you want:

percent_done = (integer) (time/current_length)*100;

Thanks a bunch Darien, I was always awful at percents

EDIT:
I had to rewrite the code because Darien's way would always return 0, so I rewrote it as so:

percent_done = (integer) ((time*100)/current_length);

Ah, no. Darien just left out a set of parenthesys.

precent_done = (integer)((time/current_length) * 100.0);

It was doing the division then converting that to an integer then multiplying that by 100. It would return 0 until the integer conversion made it a 1, then it would return 100.