Grabbing one axes?

Hi.

I want to just get the last two rotation parameters from a rotation and use them on the fly, how can I specifically get the last two, or individually rather than having to get all 4?


Thanks.

You can get the parts of a rotation or vector using x, y, z, s suffixes. This only works if you first assign them to variables, it doesn't work with a literal constant or on-the-fly result.

So, for vector v

you'll have v.x, v.y and v.z

And, for rotation r

you'll have r.x, r.y, r.z, r.s

rotation MyRot = llGetRot();
integer MyRotx = MyRot.x;
integer MyRoty = MyRot.y;
integer MyRotz = MyRot.z;
integer MyRots = MyRot.s;

You can always get the separate components of a rotation this way. However, manipulating them separately will lead to unpredictable results. Rotations are quaternions, so the x,y,z,s components cannot be interpreted directly as rotations around specific axes. If that's your purpose, you need to do something like this:

rotation x_45 = llEuler2Rot( <45 * DEG_TO_RAD, 0, 0> ); // Rotating 45 degrees around the X axis
rotation new_rot = llGetRot() * x_45;  
llSetRot(new_rot);

See http://wiki.secondlife.com/wiki/User:Void_Singer/Rotations

Puuuuuuuuuuufect.

Is there any way to use this with an object that is turning, in relation to the way the object is facing, so that it always rotates to the left (i.e. to simulate resting when being switched off)?

if you go llRot2Euler you get a vector rather than a quaternion.... so then you have control over the axes the way we lesser humans think

default
{

touch_start(integer total_number)
{
vector newrot = (llRot2Euler(llGetRot())*RAD_TO_DEG)+<0,0,30>;
llSetRot(llEuler2Rot(newrot*DEG_TO_RAD));
}
}

but if you mean "turning" via llTargetOmega, then no... as (potentially) everyone sees a different side of the turning object based on their viewer....

No, not using llTargetOmega I mean it could end up facing pretty much any random direction at the point where it gets laid to rest, so what I have been trying to do is get it to lay down to it's own left side by a certain amount of angle at the point when it gets switched off, the problem is I am having problems trying to figure out at any given time what rotation represents that rotation to its left side relative to the direction it happens to be facing.




That really helped me with something else though - thanks!