does listen event identify an integer? help

Hi guys,

I am trying to create a decimal to binary conversion in second life, but for know am trying to use the event listen to enter an input (integer) and get back an output, but thats not working, to make my self more clear consider this simple code:

-----------------

integer decimal;

default
{
state_entry()
{
llListen( 0, "", NULL_KEY, "" );
}
listen( integer channel, string name, key id, string message )
{
if ( decimal > 225 )
{
llWhisper( 0, "not acceptable" );
// open door
}
else
{
llWhisper( 0, "Hello avatar" );
// etc.
}
}
}

---------------------

know when I enter 256 am expecting the output to be (not acceptable) because the decimal I have entered is more than 255, but why am I getting (hello avatar) as an output instead?

any suggestion ?

because you're not actually putting in a decimal. it's simply looking at decimal as it is when you compile the script, which is left blank. i assume you're saying somelike like, "decimal = 256" in chat, or you're simply saying, "256"? am i right? either way that's not enough, you need to cast the number portion of the message to an integer named decimal and then compare it, IE:

decimal = (integer)message;

integer decimal;

default
{
    state_entry()
    {
        llListen( 0, "", NULL_KEY, "" ); 
    }
    listen( integer channel, string name, key id, string message )
    {
        decimal = (integer)message;
        if ( decimal > 225 )
        {
            llWhisper( 0, "not acceptable" );
            // open door
        }
        else
        {
            llWhisper( 0, "Hello avatar" );
            // etc.
        }
    }
}

Appreciated it worked.

But as I said my main objective is to create a decimal to binary conversion, as I tried to compile the original final code I had a problem here is the code :

--------------------------------

integer decimal;
integer b8 = 0;
integer b7 = 0;
integer b6 = 0;
integer b5 = 0;
integer b4 = 0;
integer b3 = 0;
integer b2 = 0;
integer b1 = 0;

default
{
state_entry()
{
llListen( 0, "", NULL_KEY, "" );
}
listen( integer channel, string name, key id, string message )
{
decimal = (integer)message;
if ( decimal > 225 )
{
llWhisper( 0, "This integer is not Accepted, Please Enter an Integer between 0 to 255" );

}
else

{
decimal = (integer)message;
if (decimal >= 12{
b8 = 1;
decimal = decimal - 128;

}

decimal = (integer)message;
if (decimal >= 64){
b7 = 1;
decimal = decimal - 64;

}

decimal = (integer)message;
if (decimal >= 32){
b6 = 1;
decimal = decimal - 32;

}

decimal = (integer)message;
if (decimal >= 16){
b5 = 1;
decimal = decimal - 16;

}

decimal = (integer)message;
if (decimal >= {
b4 = 1;
decimal = decimal - 8;

}

decimal = (integer)message;
if (decimal >= 4){
b3 = 1;
decimal = decimal - 4;

}

decimal = (integer)message;
if (decimal >= 2){
b2 = 1;
decimal = decimal - 2;
}

decimal = (integer)message;
if (decimal >= 1){
b1 = 1;
decimal = decimal - 1;
}

{
llWhisper( 0, "Binary = " + b8 = (integer)message + " " + b7 = (integer)message + " " + b6 = (integer)message + " " + b5 = (integer)message + " " + b4 = (integer)message + " " + b3 = (integer)message + " " + b2 = (integer)message + " " + b1 = (integer)message);
}

}
}
}

----------------------------

by the way the script kept compiling successfly until I have added this part:

{
llWhisper( 0, "Binary = " + b8 = (integer)message + " " + b7 = (integer)message + " " + b6 = (integer)message + " " + b5 = (integer)message + " " + b4 = (integer)message + " " + b3 = (integer)message + " " + b2 = (integer)message + " " + b1 = (integer)message);

}
---------

any suggestion ?

Maybe this totally-untested code would do it...

default
{
	state_entry()
	{
		llListen (0, "", "", "");
	}

	listen (integer channel, string from, key id, string message)
	{
		integer i = (integer)message;
		if (i == 0)
		{
			if (message == "0")
			{
				llSay (0, "0 in binary is 0");
			}

			return;
		}

		string result = "";
		while (i > 0)
		{
			if (i & 1)
			{
				result += "1";
			}
			else
			{
				result += "0";
			}

			i /= 2;
		}

		llSay (0, message + " in binary is " + result);
	}
}

that's because you can't use integers in a string function. you probably want to be something like

llWhisper( 0, "Binary = " +(string) b8 + " " + (string)b7 + " " + (string)b6 + " " + (string)b5 + " " + (string)b4 + " " + (string)b3 + " " + (string)b2 + " " + (string)b1);

When I see such a finger-breaker line, I can't resist...

For the sake of your fingers:

llWhisper(0, llDumpList2String(["Binary =", b8, b7, b6, b5, b4, b3, b2, b1], " ");

It does the conversion to strings and insert all the needed spaces in a very elegant way IMHO. Any way, here is a compact way to do your conversion:

default
{
state_entry()
{
llListen(0, "", NULL_KEY, "";
}

listen(integer channel, string name, key id, string msg)
{
integer decimal = (integer)msg;
if (decimal & 0xFFFFFF00)
{
llWhisper(0, "This value is not accepted. Please enter a value in between 0 and 255";
}
else
{
string binary;
integer i = 0;
for (; i < 8; ++i)
{
binary = (string)(decimal & 1) + binary;
decimal = decimal >> 1;
}
llWhisper(0, (string)decimal + " in binary is " + binary);
}
}
}

If you don't want the leading zeroes, just replace the 'else' block with the following:

else
{
string binary;
if (decimal)
{
while (decimal)
{
binary = (string)(decimal & 1) + binary;
decimal = decimal >> 1;
}
}
else
{
binary = "0;
}
llWhisper(0, (string)decimal + " in binary is " + binary);
}

(Quote me and you should retrieve the formating of the script.)

This is untested but I'm over-confident...

float decimal = 0.0; // this is a float not a integer
if(decimal > 255.0) // this if check now works for float values

if you where getting a user message of "255.1" it would be as text you would need
to type cast it to a float before you could check it.
listen( integer channel, string name, key id, string message )
{
float input = (float)message;
if(input > 255.0)

hope that helps ^_^

That means convert the entire message to an integer and assign it to b8, but you already assigned a value to b8.

appreciate all the help.. i'll let u know how it goes.