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Mel Fitzcarraldo
Registered User
Join date: 22 Sep 2005
Posts: 11
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06-27-2006 15:38
Greetings! I have more of a math question than a scripting question, but any adaptation to script would be appreciated also. What I'm after is the ability to move an object approximately 1-1.5m at about 27 degrees angle from whatever its position currently is, and then back again. It has to be along its primary X axis independant of which direction that is pointing. I know this involves some really neat vector math that I have long forgotten  I would draw a picture of what I want, but there's no drawing tools in the forum. I can try to elaborate further if needed. Any help is greatly appreciated! Also, if anybody has created a good vector and/or rotation library, I would be greatly interested in that also. $L interested as a matter of fact. Mel
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Ziggy Puff
Registered User
Join date: 15 Jul 2005
Posts: 1,143
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06-28-2006 09:59
Well, llRot2Fwd will give you the unit vector that represents the direction in which the object is 'facing' (i.e. the direction in which its local X axis is facing). So if you want to move 1.5m in that direction, I think your new position would be: vector newPos = llGetPos() + llRot2Fwd(llGetRot()) * 1.5; Not sure how the 27 degrees comes into play. Is it moving at 27 degrees to its forward axis? If so, then you'll need to factor that into the rotation I guess. Maybe something like this: vector newPos = llGetPos() + llRot2Fwd(llEuler2Rot(<0, 0, 27> * DEG_TO_RAD) * llGetRot()) * 1.5;
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Mel Fitzcarraldo
Registered User
Join date: 22 Sep 2005
Posts: 11
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06-29-2006 05:32
I need to read the WIKI descriptions more carefully. I think that will work! Thanks!
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