Dividing with float still rounds number?

Hello,

Suppose the following:

float num = ((13 / 10) - 1) * 10;
llOwnerSay((string)num);

Can someone tell me why num always equals 0.000 rather than 3 and how to get the correct answer out of lsl? The correct answer is 3.


Thanks.

The literals '13' and '10' are integers. When dividing an integer by an integer, integer (truncating) division is performed. It doesn't matter that later you plan to assign the result to a float; it only matters what types you are operating on in the expression. You'll want to convert (at least one of) those numbers in the division to floating point numbers before doing the division. So something like:

float num = ((13.0 / 10.0) - 1.0) * 10.0;

or even:

float num = (( ((float)13) / 10) - 1) * 10;

since the result of the first operation is a float, and each operation thereafter will result in a float since one of the operands is a float.

All of your numerical operations are on integers. The order of operations is from inside to outside, so you divide the integer 13 by the integer 10 and you get 1.3, which rounds down to 1. Then subtract 1, which makes it zero. Then multiply it by the integer 10, which is still zero. Then cast the integer result to a float, which makes it 0.0.

Have you tried float num = ((13.0/10.0) - 1.0) * 10.0 ?

I don't see how you expect to get 3 out of it.

((13/10)-1)*10 = (1.3-1)*10 = 0.3*10 = 3

Thanks guys, appreciate your time and help. I should have known better, I just forgot about the float/integer and adding a decimal to let lsl know its a float. I've probably asked this same question years ago lol.


@ SuezanneC... ((13 / 10) - 1) * 10 = 3
Look at google calculator http://www.google.ca/search?hl=en&q=%28%2813+%2F+10%29+-+1%29+*+10&btnG=Google+Search&meta=&aq=f&oq=

Thanks, I guess it's been a while since I've read any math outside the context of scripts and programs.