How to check if an integer is a multiple of a number?

i have the machine so that you pay 50L$ and i want to know how to check if the amount paid is an interval of 50L$?
this is what i have:

integer int;
        if(amount / 50 == int)
        {
//I am an interval of 50
}
 if(amount / 50 != int)
        {
//I am not an interval of 50
}

and i just tested it, and it does not work. can anyone help me?

Use the modulus (%) operator. This returns the remainder after performing integer division.

So your code would be :

if ( (amount % 50) == 0 )
{
   //  amount IS a multiple of 50
}
else
{
   //  amount IS NOT a multiple of 50
}

- Ace

ty

you can't do type checking like that. For one, if you divide two integers you get an integer, it just drops the fraction. Second there are no type checking functions, so the best way to do it is to convert everything to floats, isolate the fraction part, and see if it is not 0, the version here creates a remainder, which isn't perfect because of precision errors, but you should get the idea.

integer CONST = 50;

integer Rem(integer a, integer b)
{
    float q = ((float) a) / ((float) b);
    llWhisper(0, "q = " + (string) q);
    return (integer) ((q - ((integer) q)) * b);
}

default
{
    state_entry()
    {
        llListen(0, "", NULL_KEY, "");
    }

    listen(integer chan, string name, key id, string message)
    {
        integer r = Rem((integer) message, CONST);
        if(r == 0)
        {
            llSay(0, "Is a multiple of " + (string) CONST);
        }
        else
        {
            llSay(0, "Is not a multiple of " + (string) CONST + ". Remainder: " + (string) r);
        }
    }
}

doh, I was too slow. I forgot we could do modulus I was looking for a function to do it.
-Pat Murphy