vector string madness

Ok, maybe I'm making a error here, maybe I'm insane.

Is it possible to do something like this?


vector variable1= vector (string variable2);


So I can cheat and do things like

vector red = <1,0,0>;

listen (integer channel,string name, key id, string variable2) {

vector variable1= vector (string variable2);

}



I.E. say "red" on a channel and have it pass the string red as the actual variable name for the vector?

(Like I said, I may be insane. Oh and the above does not work in its present form).

if you want to turn a color to it's vector you need to know the vector

course you could keep a list and and just do a list find instead.

listen( integer a, string b, key c, string d)
{
    vector color = (vector)d;
    if(color == ZERO_VECTOR)
    {
        if(d == "red")
            color = <1,0,0>;
        else if(d == "green")
            color = <0,1,0>;
    }
}

Maybe you would find something useful in this script...

/15/19/71657/1.html

Assuming I've got the right idea about what you want to do, you've got the right idea, but (1) you're using the wrong syntax, and (2) you're you're using the wrong tools.

Fixing #1 first:

listen (integer channel,string name, key id, string variable2) {
    vector variable1= (vector)variable2;
}

Fixing #2... you don't use a variable, you use a list:

list name2color = [
  "red", <1,0,0>,
  "blue", <0,1,0>,
  "green", <0,0,1>,
// etcetera...
];

// and then ...

listen (integer channel,string name, key id, string variable2) {
    vector variable1;
    integer index = llListFindList(name2color, [variable2]);
    if(index = -1) variable1 = (vector)variable2;
    else variable1 = llList2Vector(name2color, index+1);
}

This way they can say "red" or "<1,0,0>" and you get the same result.

Thats what I ended up doing. Thanks!