Question about random lllFrand

Quick question about llFrand:

In the example below, if I am not mistaken, an random number will be generate ONCE then used repeatedly... OR, will the random number be re-generated each time the "timer" is set off?

default
{
    state_entry()
    {
    llSetTimerEvent(llFrand(30-15)+15);
    }

    timer()
    {
        llSay(0, "The timer has gone off.");
    }
}

In your example, the random number is generated once, and used once. The timer will be fired repeatedly.

-peekay

but in my example, the number gets randomly generated once, and for example picks 21.

Then the Timer will fire ever 21 seconds from there on out, Right?

Yes, which is what Peekay said.

Just in case you are actually looking to generate a different random number for each iteration of the timer, here's how you'd do it.

default
{
    state_entry()
    {
    llSetTimerEvent(llFrand(30-15)+15);
    }

    timer()
    {
        llSay(0, "The timer has gone off.");
        llSetTimerEvent(0); // stop the timer
        llSetTimerEvent(llFrand(30-15)+15); // restart timer with a new random number
    }
}

Thanks Guys,

I'm still somewhat new to LSL after a 15 year break from Turbo Pascal. LOL.

Just wanted to make sure I understood. Thanks for the method to reset the time too, btw.

Tuber

There is no need to stop the timer with llSetTimerEvent(0) before setting it to a new value.

-peekay

A couple of things that no one has pointed out (including me)
You need to put spaces around the minus in (30-15) or the compiler will give you a weird error emssage. But you should really be writing it as just 15, why use up extra memory you dont need to.

default 
{ 
    state_entry() 
    { 
        llSetTimerEvent(0.1); // Force the timer to fire almost immediately
    } 

    timer() 
    { 
        llSay(0, "The timer has gone off."); 
        llSetTimerEvent(llFrand(15)+15); // restart timer with a new random number 
    } 
}