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Help using or logic in if statement?
Trey Harris
Registered User
Join date: 28 Mar 2006
Posts: 8
11-19-2006 05:06
Im pretty new to LSL, I cant seem to figure out how to test something like the following.
if ( interger test != 3 or 6 or 7). I tired if ( interger test != (3 | 6 | 7)), but that did not seem to work even though it compiled ok. Please assist!!
carol Wombat
Registered User
Join date: 29 Jan 2006
Posts: 16
11-19-2006 05:25
one easy way

CODE

testFor3or6or7 (integer test) {
  if (test == 3)
    return FALSE;
  if (test == 6)
    return FALSE;
  if (test == 7)
    return FALSE;
  return TRUE;
}
carol Wombat
Registered User
Join date: 29 Jan 2006
Posts: 16
11-19-2006 05:33
A more complicated way:
CODE

if ((test != 3) &&
    (test != 6) &&
    (test != 7))
   return a false
else
  return a true



turning all that around with De Morgan:
CODE

if ((test == 3) ||
    (test == 6) ||
    (test == 7))
   return a true
else
  return a false



by the way, 3 | 6 | 7 => 7
Trey Harris
Registered User
Join date: 28 Mar 2006
Posts: 8
thank you!!
11-19-2006 06:27
Thanks alot that got it! :-)
Corey Braendle
Registered User
Join date: 26 Oct 2006
Posts: 27
11-19-2006 07:02
From: Trey Harris
I tired if ( interger test != (3 | 6 | 7)), but that did not seem to work even though it compiled ok. Please assist!!


You should have been trying a double pipe operator anyway ;)
if(blah || blah || blah)

But i dont think this works in LSL :P
Osgeld Barmy
Registered User
Join date: 22 Mar 2005
Posts: 3,336
11-19-2006 08:41
the || does not awake yet to think about syntax :)
Ordinal Malaprop
really very ordinary
Join date: 9 Sep 2005
Posts: 4,607
11-19-2006 09:52
From: Corey Braendle
You should have been trying a double pipe operator anyway ;)
if(blah || blah || blah)

But i dont think this works in LSL :P

No, there's no simple operator for that.

Overcomplex redundant way of doing it, why not:
CODE

list gValues = [3, 6, 7];

...

return (llListFindList(gValues, [test]) != -1);
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