Noob Q: llSay (0, llGetPos); ?

So yeah, I realize this is a noobish question (and that the example in the thread title is complete garbage), but how do you convert a vector into a string? I want llSay to spit out the llGetPos.

Situation: I need be able to get the local position of a child prim attached to a root.

I'm wanting to know two values, a start position and an end position, so that I can then use llSetPos to move it back and forth on command.

I've been doing it the trial-and-error way, by setting the vector, testing it, then setting it slightly over etc. However, I've got about 40 prims I need to do this to, and it sure would save a lot of time if I knew how to move it manually there, then be able to llSay the llGetPos.

I searched a bit, but couldn't seem to find an answer. I assume it's because this question is ridiculously easy, but hey, that's what makes me a noob.

Thanks in advance!

Just typecast the result:

llSay(0, (string)llGetPos());

Also, while just testing, it might be advantageous to replace the llSay with llOwnerSay.

I didn't even know there was such a thing as typecasting! That's such a vaulable concept; I know I would have found that useful in a few other projects as well.

Thanks a ton Qie

Gee, you are a newb!

Casting is extremely useful, for example, if you use a listen to "get" a value from an avatar, that will be stored in a string, yet you may want to cast it into a numeric variable such as an integer or float. For example, say you request a numeric value and use a listen to store it in a string variable called message, you can cast it into a numeric variable, then perform math on it, and then cast it back into a string (for output using llSay() ).

the format is always
(type)variable

example:
string foo = "5";
integer value = (string)foo;
foo +=1;

llSay (0,"new value=" + (string)value);

How about:


string foo = "5";
integer value = (integer) foo;
++value;

llSay (0,"new value=" + (string)value);