need help with string snippet

I'm looking for a small snippet, that would take in a string, and if it's longer then 200 characters split it into 2, without causing any words to be broken between the two... (so it looks for the first space backwards from position 200, then uses that spot to split the string into 2)

Any help would be greatly appreciated.

I think this can be done pretty easily, but it might take a little CPU time if there are a lot of spaces. I don't see a function to search backwards, so I would make it search forward until it goes past the 200th character, then back up. Also need a maximum number of words as a sanity check to avoid infinite loops. 200 words would probably be fine.

I'll give it a shot tomorrow (Wed) if I have some time.

was actually thinking on it after i posted that, and think the easiest way to do it is moving the string to a list, then one by one adding the words in the list to a temp string until it's gone past 200 length. then put the rest into the second string. Not sure if this is the most efficiant way of doing it, but it would work.

Good idea, but I don't think the lists are necessary. Add words to a second string, checking first to see if each new word will push the second string over 200 char, then start adding to a third string.

Untested code... but general idea should work... (may have to add 1 or subtract one from the final GetSubString indexes... )

string mainString = "blah blah blah... ";
string secondaryString;
 
integer stringLength = llGetStringLength( mainString );
 
if ( stringLength > 200 )
{
	integer foundSpace = FALSE;
	integer spaceNum = 200;
	while ( foundSpace == FALSE )
	{
		secondaryString = llGetSubString( mainString, spaceNum, spaceNum );
		if ( secondaryString != " " )
			--spaceNum;
		else
			foundSpace = TRUE;
	}
	secondaryString = llGetSubString( mainString, spaceNum, stringLength);
	mainString = llGetSubString( mainString, 0, spaceNum - 1);	
}

EDIT: I changed the order of the last 2 lines... changing the value of mainString 1st was just plain silly

ignore this post - RyeDin's method works just fine.
You were right, and I was wrong.
You can sing the "I was right" song

Michael - how often would you want to do this? If it is gonna be a once-off or very infrequent thing then RyeDin's solution is the easiest to understand and maintain.
But - if you need to do it often, you'll find that you need something more efficient - albeit more complex.

The average length of an English word is 6-7 letters - so think of taking a substring from, say, position 180 to position 200. It should contain 3 or 4 spaces. Find the last one in that small string rather than scanning through 200 chars. If you can't find a space there - try 160-180 and so on.

Ben, not sure why my method wouldn't be all-purpose (put into a function)?

It starts at 200 and goes back... like you said at most 5 or 6 times on average. It doesn't scan through 200 chars as you say... Can you expound?

Rye - can I blame it on a severe lack of coffee?

LOL... hmm ok let me try to remember the words to the "I was right" song. It's been such a very long time since I've been able to sing it, what with being married and all