Simple Question.....

I hope, lol

I am trying to bring a vector in from a nc, but it doesnt seem to work. Am I doing this correct or am I missing something? This is how I am doing it.

vector norm;

string norm1 = llList2String(notecardList,(index*5)+1);
norm1 = (string)norm;


Thanks for any in site I can get.

I think you want to say,

 vector norm1 = (vector) llList2String(notecardList,(index*5)+1);

Thank you!

or

vector norm1 = llList2Vector(notecardList,(index*5)+1);

No. That will *not* work. llList2Vector picks a vector out of a list.
It *does not* cast if it is not already a vector, so if your list is a list of strings, you'd get a zero-vector; the default for an invalid operation.

Opps, I stand corrected

This bit me once, which is why I remembered it.. I spent ages trying to figure out why something that worked perfectly when I read the list of vectors from the script fell over when I copied the list over to a notecard and tried to read it from there. It's the same with rotations, as I recall.

Yes, it's a fairly obscure quirk in LSL, based on the fact that list items are strongly typed.

llList2String automatically casts (since anything can be cast to string), so you can always pick something out of a list using that, but none of the other llList2... methods do; they attempt to pick out the specific type, and will return an appropriate null-value (ZERO_VECTOR, ZERO_ROTATION) if the item is not of the expected type.

ETA: llList2Key also casts, based on the fact that keys for all practical purposes are treated as strings, nevermind whether what's in them is on the format of a key, let alone a valid key.

you pretty much have two choices, cast it to a vector when you get it from a notecard (preferable) or cast it to a vector when you use it... stupid, but true.

All of the llList2*() functions cast EXCEPT for llList2Vector() and llList2Rot(). I'd actually prefer that NONE of them did except for llList2String(), but there you go.