Setting Rot

This is a completely lame question. And I'm sure the answer is simple, but for one reason or another I'm overcomplicating the task at hand and am in a rut.

I'm trying to rotate a child prim and only on the x axis, and for some reason or another it is rotating all the axis'.

IE

llSetRot(llEuler2Rot(<-5,0,0>);

It works, but screws around with the Y and Z as well setting them to 0. Yeah, plain as day right there, that's what I typed in isn't it? Well, I really just meant by 0: don't change a thing.

So my question is...what do I do instead of putting 0 there? Do I need to llGetLocalRot and use those results and add only the X axis change every time I change the rot of this prim.

BTW- Think wings here, I'm trying to make something flap up and down.

I'm in world right now as well, if you happen to be online and going online sometime soon. Otherwise, I'll keep checking the boards here for a reply.

Thanks

Your problem is that llEulerToRot wants it's parameter in radians, and you're giving it in degrees. Try this...

llSetRot(llEuler2Rot(<-5,0,0> * DEG_TO_RAD));

Thank you Kermitt! I just logged out of world, so I'll give my script an update tomorrow. Appreciate the help.

Recommend using AxisAngle2Rot, it's intuitive and practically a quaternion (which is what SL uses internally).

Azelda

Thanks Azelda,

Going to give that a try. The first suggestion didn't work unfortunately, so still stumped over this seemingly simple function I want to incorporate into my prims.

-Omen

btw, you probably want to use llSetLocalRot if its a child prim. Sortof semi-critical bit of info that

Azelda

Hehe yes. The original post was actually a misprint in that respect. I should have just copy/pasted from the script window, but I hashed it out on screen and completely didn't notice I'd used the regular function instead of local. Thanks for the info anyway, just incase that had been the situation.