Converting llGetTimeOfDay to hrs/mins?

I just started to get down with LSL today and was looking to hack up a module that can give me things like time of day in the sim I'm in, location, etc, etc. I've seen alot of threads alluding to some of these things, but none that could tell me how to convert the output of llGetTimeOfDay() to hrs/mins. Here's what I have so far:

default
{
    state_entry()
    {
    
    }

    touch_start(integer total_number)
    {
       float time = llGetTimeOfDay();
       llSay(0, "The time is " + (string)time);       
    }
}

'preciate any science someone can drop on me regarding this. I expect to be posting more in terms of calls for clue as I get up to speed on LSL. Until then, be easyl.

the same way as the example of llGetWallClock on the wiki, but it only deals with sim time, which 1 day is 4 hours long and it goes to 0 apon a sim reset ect

integer simtime;
integer h;
integer m;
integer s;
default
{
    touch_start(integer total_number)
    {
        simtime = (integer)llGetTimeOfDay();
        h = simtime/3600;
        m = (simtime%3600)/60;
        s = simtime%60;
        llSay(0,(string)h+":"+(string)m+":"+(string)s);
    }
}

Thanks for the clue Osgeld. I noticed that the output for say, 8:01:02 is displayed as: 8:1:2. Is there a way around that?

Yes, there is, but it's a fiddle.

You need to typecast the minutes and seconds to strings, check their length, and if it's 1 add a 0 in front.

Something like this snippet:

string min=(string)m;
if(llStringLength(min)==1)
{
    min="0"+min;
}

You can actually define that as a function if you want (since you'll do the same for seconds too, or as it's so short just write it again) and your output string would become llSay(0, (string)h+":"+min+":"+sec);

Silly question but why not use llGetTimestamp?

Hmm, I guess my assumption was that it wouldn't give you actual time in SL for the particular sim you're in. I thought it was based on RL time.