lslint: Expression and constant without operator.

in lslint i get:

"Expression and constant without operator"

for this:

integer tmpfloornum = (integer)floor_num - 1 ;

still get it even when I recast it like this:

integer tmpfloornum;
tmpfloornum = ( (integer)floor_num-1 );

what am I not seeing here?

I expect this code is outside any function or state, IE in the global section of your script. You cannot use expressions in the global section.

If that's not the case, I suggest you post the code...

What did you put into floor_num?

When you typecast an expression, the expression must be in parenthesis. Your line should be:

integer tmpfloornum = (integer)(floor_num - 1) ;

Put a space before and after the minus sign. LSL has a bug in its interpretation of negative signs versus minus signs, and lslint probably checks to make sure you're not going to trigger it with your code.

The full error should read:

ERROR:: ( 5, 35): Expression and constant without operator.
Are you doing `foo-2`? Separate operators with spaces.
See: http://secondlife.com/badgeo/wakka.php?wakka=knownbugs

Are you not getting the additional lines anywhere? What editor are you using?
edit: I gotta fix the links sometime, http://lslwiki.net/lslwiki/wakka.php?wakka=KnownBugs

hmm, have tried all these suggestions and more, but nothing will make lslint happy.

But you know, the code actually works inworld, so I'm going to just leave it as is and forget about it.