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Gruntos Baxter
Registered User
Join date: 15 Jan 2007
Posts: 20
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02-23-2007 08:17
I tried to make a list in a list yesterday and it failed so I take it this is not supported? I see List of all sorts but not lists of lists
for example list fred = [1,2 3 4] list wilma = [5,6,7,8] list all = [fred,wilma]
fails with Function Args: s Local List: (null) Function Args: (null)
Failing that can I pass the address of a list to a function and use that? liek a referance or a pointer?
The other thing is I create a string of "fred,wilma" and use llParseString2List but how do i then de-referance the lists as I will then get ["fred","wilma"] and not address of list fred and wilma.
The more I program I find serious limitations using SL Scripting
Is there a hashing system ?
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Lee Ponzu
What Would Steve Do?
Join date: 28 Jun 2006
Posts: 1,770
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02-23-2007 08:31
No list of lists. No pointers.
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Newgate Ludd
Out of Chesse Error
Join date: 8 Apr 2005
Posts: 2,103
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02-23-2007 09:28
list fred = [ "barney", "dino" ]; list wilma = [ "betty", "pebbles" ]; list all = fred + wilma; // will beone list containing the contents of both fred and wilma
If each list is a fixed known length then use a strided list You can pass a list to a function, but they are pass by value so its very easy to eat script memory.
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Lex Neva
wears dorky glasses
Join date: 27 Nov 2004
Posts: 1,361
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02-23-2007 12:22
Yeah, LSL is pretty limited in this respect.
You can, if you really want to, store a list of strings that you parse into lists, like this:
list fredwilma=["1,2,3,4", "5,6,7,8"];
Then use llCSV2List and llList2CSV to get at the sublists. It's totally inefficient.
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Gruntos Baxter
Registered User
Join date: 15 Jan 2007
Posts: 20
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02-23-2007 14:36
what I wanted to do was run a for next loop running a different list on each index
saying that <thinks aloud> I could create one list containing long strings and then run pharstring2list on each one
that might work somthing like fred = ["this is list one","this is list 2",...] and look around each list element which is a string and then pharse that
Yea
Same No * or &
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Newgate Ludd
Out of Chesse Error
Join date: 8 Apr 2005
Posts: 2,103
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02-23-2007 14:50
or you could just check which index your in and pass a copy of the list to a function. if(1 == index) Process(Fred); else if(2 == index)Process(Wilma);
messy but workable. At least for small numbers. What are you actually trying to do?
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