Looking for specific Date function.

I'm looking for a specific Date function that, given a time in seconds, it returns Day, Month and Year.

For example today is Saturday:

integer timeLeft = 86400; //24hs
list dateData = returnDate(timeLeft);

The result of the list should be:

["2009","February","Sunday"];

If someone has something that could look like this please share it... otherwise I will have to write it by myself and I'll post the solution here

I haven't played with them at all, but I notice that there are a few sample scripts on the LSL wiki at that come fairly close to what you want to do ..... at least close enough to save you some coding trouble.

There is no calendar function in LSL. While you can get the current date with a couple of different calls, to get the day of week/date for a different day you will need to create your own calendar taking into account days per month and leap year etc.

/54/45/302481/1.html might be of some value.

I suppose I'll have to do it by myself...there should be default Calendar functions in LSL, almost every programming language have them.

Looks to me like the last example in Rollig's wiki link above will only take minor tampering to do what you want.

http://en.wikipedia.org/wiki/Perpetual_calendar has a good formula for grabbing the day of the week for dates 1901-2099

//-- how you fill these three is up to you, llGetDate works, but you may want timestamp to get a correct hour offset.
integer gIntYear;
integer gIntMonth;
integer gIntDayOfMonth;

//-- month names included so you can print the friendly name
list   gLstMonth = ["January", 0, "February", 3, "March", 3, "April", 6, "May", 1, "June", 4, "July", 6, "August", 2, "September", 5, "October", 0, "November", 3, "December", 5];
list   gLstDOW = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];

integer vIntDOW   = gIntYear + (integer)(gIntYear / 4.0) + llList2Integer(gLstMonth, gIntMonth * 2 + 1) + gIntDayOfMonth - 2;
if ( !(gIntYear % 4) && gIntMonth < 2){
  gIntDOW -= 1;
}
llSay( 0, lList2String( gLstDOW, gIntDOW ) + ", " +  lllList2String( gLstMonth, gIntMonth * 2) + " " + (string)gIntDayOfMonth + ", " + (string)gIntYear );

ETA: minor typo + correction in leap year formula

I started some work on this kind of thing here:

/54/45/302481/1.html

It includes functions that will return the day of the week for ANY valid Gregorian date ('weekdayOfDay' and 'weekdayOfDate'). You could also use 'daysBetween' or 'daysBetweenDates' to do the opposite calculation: how many days between "the epoch" and a particular date (times 86400 of course to get seconds). It doesn't deal with leap-seconds, but few applications need to be THAT precise.

I'll see if I can work up a solution for this kind of problem as well and add it to that library. And maybe get it over to the wiki at some point. LOL.

I just added some functions to the thread I linked to above. In particular, the 'daysAfter' or 'daysAfterDate' functions may be of help, though for this particular application you'll have to include in your own code the definition of "the epoch" and the logic to convert seconds to days.

I haven't compiled or tested that addition yet. I'll be working on that over the next couple of days. Just wanted to let you know it's there and might (now or eventually) be of help. Heck, it might even just work. If you want to help test it, that's always appreciated.

Thanks Hewee!, this solves my problem.