Moving linked prims... $L500 for an answer.

Example:

Here we see two must-be-linked primitives. The horizontal prim is the parent.


. . |
. . |
----------
. . |
. . |

I can move the vertical prim up and down in relation to the parent with llSetPos() easily enough.

Now here's what I'm trying to do:


. . . . ./
. . . . /
----------
. . . /
. . ./


Here, the vertical prim is on an angle, and when I move it up and down, I want it to move along it's own Z axis. That is, up and down diagonally.

Can someone help me out?

L$500 for a solution.

Wouldn't that just be:

vector zMove = <0.0, 0.0, 1.0>;
llSetPos(llGetLocalPos() + (zMove * llGetLocalRot()));

then set zMove = -1 * zMove to move back down?

llSetPos(destpos*llGetRot()); ?

Create a 3rd prim, make it invisible and use it as the root so local set pos's will work the way you expect?

Doesnt he have to factor in the parent objects rotation as well? The new llGetRootRot is really handy for that. It used to be that we had to get it with link messages.

No, sub object position is relative to the root object, not the world co-ordinate system.

So make this...

       |
       |   /
       | /
       /
     / |
   /   |
       |

And make the / prim move up and down straight. Then tip the whole thing on its side a bit so the | line is / and the / line is --. Since the motion is relative to the root prim, you can rotate the whole thing so it looks right after building it to move in ordinal directions.

Thank you Mr. Grimm! Works like a charm.

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