How can I do this?
touch_start(integer total_number)
{
vector vecOne = <10, 5, 10>;
vector vecTwo = <5, 5, 5>;
vector vecThree = vecOne * vecTwo;
llSay(0, (string)vecThree);
}
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Nyx Alsop
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01-16-2010 13:58
How can I do this?
touch_start(integer total_number) { vector vecOne = <10, 5, 10>; vector vecTwo = <5, 5, 5>; vector vecThree = vecOne * vecTwo; llSay(0, (string)vecThree); } |
Dora Gustafson
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01-16-2010 14:08
How can I do this? touch_start(integer total_number) { vector vecOne = <10, 5, 10>; vector vecTwo = <5, 5, 5>; vector vecThree = vecOne * vecTwo; llSay(0, (string)vecThree); } float f = vecOne * vecTwo; The other product is a CROSS product and results in a vector perpendicular to both vectors in the argument: vector vecThree = vecOne % vecTwo; _____________________
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Void Singer
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01-16-2010 14:26
if you are expecting a result of <50, 25, 50> you'll need to multipl each element separately....
vector vecOne = <10, 5, 10>; vector vecTwo = <5, 5, 5>; vector vecThree = < vecOne.x * vecTwo.x, vecOne.y * vecTwo.y, vecOne.z * vecTwo.z >; alternatively, if you know all the elements in one of the vectors are the same, you can do this vector vecOne = <10, 5, 10>; float fltTwo = 5.0; vector vecThree = vecOne * fltTwo; _____________________
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Rolig Loon
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01-16-2010 14:34
There's a big difference between vector multiplication (dot product or cross product), which Dora was describing, and scalar multiplication, which is what Void was describing. The OP better be sure that he knows which one he wants to do.
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Void Singer
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01-16-2010 15:11
yup, and many expect the latter to occur with the former operator...
out of curiousity, would my first example actually be considered scalar? I'd think so, just with a variable magnitude, versus a universal one... but I'm not sure... calc was so long ago. ps is it just me or are operators and precedence (my two original post excepted) coming up a lot more recently? _____________________
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Nyx Alsop
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01-16-2010 15:28
I understand what a dot product is, but could someone tell me why it's usful? I know it's the same in Matrix multiplcation, but I never really understand why it's useful?
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Rolig Loon
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01-16-2010 15:43
The dot product of two vectors a and b is == |a| *|b| *cos Theta, where |a| and |b| denote the length of a and b and Theta is the angle between them. Among other things, this means that given two vectors, the angle between them can be found by rearranging this to get
Theta = arccos (( a . b)/(|a| *|b|)) . Kind of a useful function. _____________________
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Void Singer
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01-16-2010 15:56
also useful if you want to do matrix operations using vectors to store the lists instead of storing all those variables separately and then doing it all long hand... makes solving equations in 2 coefficients a heck of a lot faster =)
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Dora Gustafson
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01-17-2010 02:59
I understand what a dot product is, but could someone tell me why it's usful? I know it's the same in Matrix multiplcation, but I never really understand why it's useful? http://en.wikipedia.org/wiki/Dot_product _____________________
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