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David Guillaume
Registered User
Join date: 15 May 2004
Posts: 10
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10-27-2004 21:40
llDetectedArc() (sensors only)
We already know the server is calculating this for every object a sensor picks up to ridiculous precision anyway. Why not have an llDetected function for so we can use it when it's needed instead of using other functions to reinvent it?
llDetectedMass()
Again, the server has already calculated it and it would be so useful for better shielding technologies and maybe some fun physics toys. Why not allows us to identify it easily instead of guessing?
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Huns Valen
Don't PM me here.
Join date: 3 May 2003
Posts: 2,749
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11-01-2004 11:17
Definitely in support of llDetectedMass(). What would llDetectedArc() indicate exactly?
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Cashmere Falcone
Prim Manipulator
Join date: 21 Apr 2004
Posts: 185
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11-01-2004 15:30
llDetectedArc
I think what he is saying, is that would allow a sensor to operate within a certain arc, instead of radiating out equally in all directions. Makes sense, put a sensor in a corner of a room and scan 90 Degrees of a circle (the room) instead of 360 degrees. would make scan information a lot more accurate and should lesson the sim lag caused by scanners, since its not scanning such a large area.
llScanArc(parameters +x[ out X # of meters], +y[out X number of meters], at Z[height parameters]);
_____________________
Jebus Linden for President! 
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Moleculor Satyr
Fireflies!
Join date: 5 Jan 2004
Posts: 2,650
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11-01-2004 16:42
Actually, you can do the Arc thing already. Just put something smaller than PI in as your... arc.
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Jillian Callahan
Rotary-winged Neko Girl
Join date: 24 Jun 2004
Posts: 3,766
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11-01-2004 17:00
I suspect llDetectedArc would be the rotation that would point the prim with the sensor in to at the obeject, or something similar. Though, we have several ways to do that already, not the least of which is llLookAt.
ok, maybe not. Frankly, I'm guessing. 'avent a bloody clue.
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Huns Valen
Don't PM me here.
Join date: 3 May 2003
Posts: 2,749
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11-02-2004 09:38
Maybe he means degrees of arc from the bottom left edge of the volume being scanned. Then it would be a vector, since we are in three-space...? I am not sure :|
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